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Nanaba
@Nanaba
May 2019
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Bonjour, pouvez vous m'aidez pour ce calcul svp .
Il faut développer puis réduire
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maudmarine
Verified answer
Bonjour,
a = (2x + 1)² - (x + 3)²
a = 4x² + 4x + 1 - (x² + 6x + 9)
a = 4x² + 4x + 1 - x² - 6x - 9
a = 4x² - x² + 4x - 6x + 1 - 9
a = 3x² - 2x - 8
1 votes
Thanks 1
LaPerlEDeMath
Verified answer
bonsoir =)
développer puis réduire
A = (2x +1)² - (x+3)²
= 4x² + 4x + 1 - ( x² + 6x + 9)
= 4x² + 4x +1 -x² -6x -9
= 4x² - x² + 4x - 6x + 1 - 9
= 3x² - 2x - 8
voilà =)
1 votes
Thanks 1
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Lista de comentários
Verified answer
Bonjour,a = (2x + 1)² - (x + 3)²
a = 4x² + 4x + 1 - (x² + 6x + 9)
a = 4x² + 4x + 1 - x² - 6x - 9
a = 4x² - x² + 4x - 6x + 1 - 9
a = 3x² - 2x - 8
Verified answer
bonsoir =)développer puis réduire
A = (2x +1)² - (x+3)²
= 4x² + 4x + 1 - ( x² + 6x + 9)
= 4x² + 4x +1 -x² -6x -9
= 4x² - x² + 4x - 6x + 1 - 9
= 3x² - 2x - 8
voilà =)