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Bertille20
@Bertille20
May 2019
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Bonjour pouvez vous résoudre l'équation avec un niveau enviro 3e: (x+5)^2 = 7x (x+5) merci
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taalbabachir
Verified answer
(x + 5)² = 7 x (x + 5) ⇔ (x + 5)² - 7 x(x + 5) = 0
(x + 5)(x + 5 - 7 x) = 0
(x + 5)(5 - 6 x) = 0 ⇒ x + 5 = 0 ⇒ x = - 5 ou 5 - 6 x = 0 ⇒ x = 5/6
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inequation
Bonsoir,
Résoudre l'équation
(x+5)² = 7x (x+5)
(x+5)(x+5) - 7x (x+5) =0
(x+5)(x+5-7x)= 0
(x+5)(-6x+5)=0
x+5=0 ou -6x+5=0
x= -5 -6x= -5
x= 5/6
S= {-5; 5/6}
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Bertille20
May 2019 | 0 Respostas
Combien font 7x (x+5) ?
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Verified answer
(x + 5)² = 7 x (x + 5) ⇔ (x + 5)² - 7 x(x + 5) = 0(x + 5)(x + 5 - 7 x) = 0
(x + 5)(5 - 6 x) = 0 ⇒ x + 5 = 0 ⇒ x = - 5 ou 5 - 6 x = 0 ⇒ x = 5/6
Résoudre l'équation
(x+5)² = 7x (x+5)
(x+5)(x+5) - 7x (x+5) =0
(x+5)(x+5-7x)= 0
(x+5)(-6x+5)=0
x+5=0 ou -6x+5=0
x= -5 -6x= -5
x= 5/6
S= {-5; 5/6}