bonjour
1
vect AC (xc-xa ; yc-ya) = (-5 ; 3)
x1/4 = (-5/4 ; 3/4)
et vect BC (-2 ; -2)
x1/2 (-1 ; -1)
donc 1/4AC-1/2BC (-5/4-(-1)) ; 3/4-(-1) = (-1/4 ; 7/4)
2
xm - xc = -1/4
xm = -1/4 + (-2) = -9/4
et
ym - yc = 7/4
ym = 7/4 + 2 = 15/4
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Verified answer
bonjour
1
vect AC (xc-xa ; yc-ya) = (-5 ; 3)
x1/4 = (-5/4 ; 3/4)
et vect BC (-2 ; -2)
x1/2 (-1 ; -1)
donc 1/4AC-1/2BC (-5/4-(-1)) ; 3/4-(-1) = (-1/4 ; 7/4)
2
xm - xc = -1/4
xm = -1/4 + (-2) = -9/4
et
ym - yc = 7/4
ym = 7/4 + 2 = 15/4