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Siham34070
@Siham34070
May 2019
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Bonjour, qui peut m'aider? developper et réduire : A= 3(2x+1) B= -2(x-1)+x C=)2x+1)(x+3) QUAND JE MET ''x'' C'EST LA LETTRE ET NON L'UNITÉ MULTIPLIER
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Mohamed120
Bonjours
(A):3(2x+1)= 3*2x + 1*3 =
6x+3
(B): -2(x-1)+x=-2*x -2*(-1) +x=-2x+x+2=
x+2
(C): (2x+1)(x+3)=2x*x+2x*3+1*x+1*3=2x²+6x+x+3=
2x²+7x+3
0 votes
Thanks 1
charonnelamiss
de rien
charonnelamiss
Bonsoir a=6x+3 b=x+1 c=2xau carrer+6x+1x+3
=2xau carrer+7x+3 jespere ke ces sa si je ne me trompe pas
0 votes
Thanks 1
charonnelamiss
de rien
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(A):3(2x+1)= 3*2x + 1*3 =6x+3
(B): -2(x-1)+x=-2*x -2*(-1) +x=-2x+x+2=x+2
(C): (2x+1)(x+3)=2x*x+2x*3+1*x+1*3=2x²+6x+x+3= 2x²+7x+3
=2xau carrer+7x+3 jespere ke ces sa si je ne me trompe pas