Réponse :
Bonjour
cos(α) = 2/5
on a cos²(α) + sin²(α) = 1
donc sin²(α) = 1 - cos²(α) = 1 - (2/5)² = 1 - 4/25 = 21/25
donc sin(α) = √(21/25) = √21/5
tan(α) = sin(α)/cos(α) = (√21/5)/(2/5) = (√21/5) × 5/2 = √21/2
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Réponse :
Bonjour
cos(α) = 2/5
on a cos²(α) + sin²(α) = 1
donc sin²(α) = 1 - cos²(α) = 1 - (2/5)² = 1 - 4/25 = 21/25
donc sin(α) = √(21/25) = √21/5
tan(α) = sin(α)/cos(α) = (√21/5)/(2/5) = (√21/5) × 5/2 = √21/2