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Laura97
@Laura97
April 2019
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Bonjour, qui pourrait m'aidez ?
Soit A = (4x-3)²-(6x+1)(4x-3)
1) dévellopper et reduire A
2) Factoriser A
Soit B = (3x+1)²-25
1) développer et reduire B
2) factoriser b
merci pour votre aide
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nonotata
) dévellopper et reduire A
A = (4x-3)²-(6x+1)(4x-3)
a = 16x²-24x+9 -(24x²-18x+4x-3)
a = 16x² -24x+9 -24x² +14x+3
a = -8x² -10x+12
2) Factoriser A
A = (4x-3)²-(6x+1)(4x-3)
a =(4x-3)(4x-3-6x-1)
a =(4x-3)(-2x-4)
a = -2(4x-3)(x+2)
Soit B = (3x+1)²-25
1) développer et reduire B
B = (3x+1)²-25
b = 9x²+6x+1-25
b = 9x²+6x -24
2) factoriser b
B = (3x+1)²-25
B = (3x+1)²-5²
b =(3x+1-5)(3x+1+5)
b =(3x-4)(3x+6)
b =3(3x-4)(x+2)
2 votes
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A = (4x-3)²-(6x+1)(4x-3)
a = 16x²-24x+9 -(24x²-18x+4x-3)
a = 16x² -24x+9 -24x² +14x+3
a = -8x² -10x+12
2) Factoriser A
A = (4x-3)²-(6x+1)(4x-3)
a =(4x-3)(4x-3-6x-1)
a =(4x-3)(-2x-4)
a = -2(4x-3)(x+2)
Soit B = (3x+1)²-25
1) développer et reduire B
B = (3x+1)²-25
b = 9x²+6x+1-25
b = 9x²+6x -24
2) factoriser b
B = (3x+1)²-25
B = (3x+1)²-5²
b =(3x+1-5)(3x+1+5)
b =(3x-4)(3x+6)
b =3(3x-4)(x+2)