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Laura97
@Laura97
April 2019
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Bonjour qui pourrez m’aidé s'il vous plait ? Niveau 3e
Soit A = (3x+1)²-(2x-5)(3x+1)
1) Développer et réduire A
2) Factoriser A
3) développer le résultat de la question 2). Qu'obtient-on ?
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elise77
1) A=(3x+1)^2-(2x-5)(3x+1)
A=(9x^2+6x+1)-(6x^2+2x-15x-5)
A=9x^2+6x+1-6x^2+13x+5
A=3x^2+19x-6
2) A=(3x+1)^2-(2x-5)(3x+1)
A=(3x+1)[(3x+1)-(2x-5)]
A=(3x+1)(3x+1-2x+5)
A=(3x+1)(x+6)
3) A=(3x+1)(x+6)
A=3x^2+18x+x+6
A=3x^2+19x+6
on obtient le résultat de la forme développé de A.
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A=(9x^2+6x+1)-(6x^2+2x-15x-5)
A=9x^2+6x+1-6x^2+13x+5
A=3x^2+19x-6
2) A=(3x+1)^2-(2x-5)(3x+1)
A=(3x+1)[(3x+1)-(2x-5)]
A=(3x+1)(3x+1-2x+5)
A=(3x+1)(x+6)
3) A=(3x+1)(x+6)
A=3x^2+18x+x+6
A=3x^2+19x+6
on obtient le résultat de la forme développé de A.