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Laura97
@Laura97
April 2019
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Bonjour, qui pourrez nous aidé en mathématiques niveau 3e ? C'est pour mon frère. Merci d'avance.
Développer et réduire les expressions suivantes :
A= -2(7x+4)²
B= (3x-2)(3x+2)+(2x-5)²
C= 3(x+3)²-(2x-1(3x+1)
Exercice 2 :
Factoriser les expressions suivantes
E = 9x²-24x+16
F = (x+1) (x+3)-5(x+3)
G = 100t²-121
H = (4x+1)(7x+2)+(4x+1)²
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winner123
Verified answer
Bonjour
A = - 2 ( 49 x² + 56 x + 16)
A = - 98 x² - 112 x - 32
B = 9 x² + 6 x - 6 x - 4 + 4 x² - 20 x + 25
B = 13 x² - 20 x + 21
c = 3( x² + 6 x +9) - ( 6 x² + 2 x - 3x - 1)
C = 3 x² + 18 x + 27 - 6 x² - 2 x + 3 x + 1
C = - 3 x² + 19 x + 28
E = ( 3 x - 4)²
F = (x +3) ( x +1 - 5)
f = ( x +3) ( x -4)
G = ( 10 t - 11) ( 10 t +11)
h = ( 4 x +1) ( 7 x +2 + 4 x +1)
H = ( 4 x +1) ( 11 x + 5)
1 votes
Thanks 1
nathalienouts
Développer et réduire les expressions suivantes :
A= -2(7x+4)²
A = -2(49x²+56x+16)
A = -98x²-112x-32
B= (3x-2)(3x+2)+(2x-5)²
B= (9x²+6x-6x-4)+(4x²-20x+25)
B = 9x²-4+4x²-20x+25
B = 13x²-20x+21
C= 3(x+3)²-(2x-1)(3x+1)
C = 3(x²+6x+9)-(6x²+2x-3x-1)
C = 3x²+18x+27-6x²+x+1
C = -3x²+19x+28
Exercice 2 :
Factoriser les expressions suivantes
E = 9x²-24x+16 identité remarquable (a+b)² = a²+2ab+b²
E = (3x-4)²
F = (x+1) (x+3)-5(x+3) on met x+3 en facteur
F = (x+3)(x+1-5)
F = (x+3)(x-4)
G = 100t²-121 identité remarquable a²-b² = (a+b)(a-b)
G =(10t)²-11²
G = (10t+11)(10t-11)
H = (4x+1)(7x+2)+(4x+1)² on met 4x+1 en facteur
H = (4x+1)(7x+2+4x+1)
H = (4x+1)(11x+3)
2 votes
Thanks 1
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Verified answer
BonjourA = - 2 ( 49 x² + 56 x + 16)
A = - 98 x² - 112 x - 32
B = 9 x² + 6 x - 6 x - 4 + 4 x² - 20 x + 25
B = 13 x² - 20 x + 21
c = 3( x² + 6 x +9) - ( 6 x² + 2 x - 3x - 1)
C = 3 x² + 18 x + 27 - 6 x² - 2 x + 3 x + 1
C = - 3 x² + 19 x + 28
E = ( 3 x - 4)²
F = (x +3) ( x +1 - 5)
f = ( x +3) ( x -4)
G = ( 10 t - 11) ( 10 t +11)
h = ( 4 x +1) ( 7 x +2 + 4 x +1)
H = ( 4 x +1) ( 11 x + 5)
A= -2(7x+4)²
A = -2(49x²+56x+16)
A = -98x²-112x-32
B= (3x-2)(3x+2)+(2x-5)²
B= (9x²+6x-6x-4)+(4x²-20x+25)
B = 9x²-4+4x²-20x+25
B = 13x²-20x+21
C= 3(x+3)²-(2x-1)(3x+1)
C = 3(x²+6x+9)-(6x²+2x-3x-1)
C = 3x²+18x+27-6x²+x+1
C = -3x²+19x+28
Exercice 2 :
Factoriser les expressions suivantes
E = 9x²-24x+16 identité remarquable (a+b)² = a²+2ab+b²
E = (3x-4)²
F = (x+1) (x+3)-5(x+3) on met x+3 en facteur
F = (x+3)(x+1-5)
F = (x+3)(x-4)
G = 100t²-121 identité remarquable a²-b² = (a+b)(a-b)
G =(10t)²-11²
G = (10t+11)(10t-11)
H = (4x+1)(7x+2)+(4x+1)² on met 4x+1 en facteur
H = (4x+1)(7x+2+4x+1)
H = (4x+1)(11x+3)