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Lirignia
@Lirignia
April 2019
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Bonjour ,
Résoudre F=0 ????
F = (3x-5)² - (3x-5)(x+4)
Merci d'avance
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Bonsoir,
(3x-5)² - (3x-5)(x+4) = 0
(3x-5)(3x-5) - (3x-5)(x+4) = 0
(3x-5)[(3x-5) - (x+4)] = 0
(3x-5)(3x-5 - x-4) = 0
(3x-5)(2x-9) = 0
3x-5 = 0 ou 2x-9=0
3x=5 ou 2x=9
x= 5/3 ou x=9/2
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(3x-5)² - (3x-5)(x+4) = 0
(3x-5)(3x-5) - (3x-5)(x+4) = 0
(3x-5)[(3x-5) - (x+4)] = 0
(3x-5)(3x-5 - x-4) = 0
(3x-5)(2x-9) = 0
3x-5 = 0 ou 2x-9=0
3x=5 ou 2x=9
x= 5/3 ou x=9/2