Bonjour si vous pourriez m'aider , je ne refuserai pas !
Merci d'avance ! ( développez s'il vous plait )
Sachant que:- y X z = y+z
- y : z = y-z
- (10^y)^z = 10^yXz
^y = puissance y
Merci
Merci d'avance ! ( développez s'il vous plait )
Sachant que:- y X z = y+z
- y : z = y-z
- (10^y)^z = 10^yXz
^y = puissance y
Merci
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Bonjour
A = (2 x 10^-3 x 15 x (10^2)^2) / (10^-4 x 50 x 10^-5)
= [ (2 x 15) / 50 ] x [ (10^-3 x (10^2)^2) / (10^-4 x 10^-5) ]
= (30 / 50) x (10^-3+2x2 / 10^-4-5)
= 0.6 x (10^1 / 10^-9)
= 0.6 x 10^1+9
= 0.6 x 10^10
= 6 x 10^-1 x 10^10
= 6 x 10^-1+10
= 6 x 10^9
B = (2 + 2/3) / (4/5 - 2/3)
= [ (2 x 3)/(1 x 3) + 2/3 ] / [ (4 x 3)/(5 x 3) - (2 x 5)/(3 x 5) ]
= (6/3 + 2/3) / (12/15 - 10/15)
= [ (6+2)/3 ] / [ (12-10)/15 ]
= 8/3 / 2/15
= 8/3 x 15/2
= (8 x 15) / (3 x 2)
= (2 x 4 x 3 x 5) / (3 x 2)
= 20
= 2 x 10^1
C = 6 x (5^2 - 2^-1) + 5 x 10^2
= 6 x (25 - 0.5) + 500
= 6 x 24.5 + 500
= 147 + 500
= 647
= 6.47 x 10^2
D = 1/3 + 2/3 x (1/4 - 5/12)
= 1/3 + 2/3 x [ (1 x 3)/(4 x 3) - 5/12 ]
= 1/3 + 2/3 x (3/12 - 5/12)
= 1/3 + 2/3 x [ (3-5)/12 ]
= 1/3 + 2/3 x (-2/12)
= 1/3 + 2/3 x (-1)/6
= 1/3 + (2 x (-1))/(3 x 6)
= 1/3 + (2 x (-1))/(3 x 2 x 3)
= 1/3 + (-1)/9
= (1 x 3)/(3 x 3) - 1/9
= 3/9 - 1/9
= (3-1)/9
= 2/9
Voilà j'espère avoir pu t'aider ^^