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Amel84
@Amel84
May 2019
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Bonjour svp je vous en supplie aider moi je vous en supplie s'il vous plaît
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Bonsoir,
exo 1 :
1) BK :
BK = AE
thales ds ASH
AE/AH = AJ/AS =
JE/SH
AH = 4m
JE = 2,5-1 = 1,50m
SH = 3,5-1 = 2,5m
AE/4 = 1,5/2,5
AE = (1,5*4)/2,5 = 2,40m
AE=BK = 2,4m
b) KL = BC-(BK+LC)
= 8-(2,4+2,4) = 3,2m
exo 2 :
1) on calcule AD :
(BC)//(DE)
⇒thales
AB/AE = AC/AD = BC/DE
400/1200 = 300/AD
AD = (1200*300)/400 = 900m
on calcule CD :
CD =
AD-AC = 900-300
= 600m
2) on calcule BC :
CAB rectangle en A
⇒pythagore
BC² = AB²+AC²
= 400²+300²
BC =
√250000 =
500m
3) on calcule DE :
(BC)//(DE)
⇒thales
AB/AE
= AC/AD =
BC/DE
400/1200 = 500/DE
DE
= (1200*500)/400
= 1500m
parcours : AB+BC+CD+DE
tu as ttes les longueurs,
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amel84
January 2021 | 0 Respostas
URGENT SVP aidez moi merci!!!!!!!!!!
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Verified answer
Bonsoir,exo 1 :
1) BK :
BK = AE
thales ds ASH
AE/AH = AJ/AS = JE/SH
AH = 4m
JE = 2,5-1 = 1,50m
SH = 3,5-1 = 2,5m
AE/4 = 1,5/2,5
AE = (1,5*4)/2,5 = 2,40m
AE=BK = 2,4m
b) KL = BC-(BK+LC)
= 8-(2,4+2,4) = 3,2m
exo 2 :
1) on calcule AD :
(BC)//(DE)
⇒thales
AB/AE = AC/AD = BC/DE
400/1200 = 300/AD
AD = (1200*300)/400 = 900m
on calcule CD :
CD = AD-AC = 900-300 = 600m
2) on calcule BC :
CAB rectangle en A
⇒pythagore
BC² = AB²+AC²
= 400²+300²
BC = √250000 = 500m
3) on calcule DE :
(BC)//(DE)
⇒thales
AB/AE = AC/AD = BC/DE
400/1200 = 500/DE
DE = (1200*500)/400 = 1500m
parcours : AB+BC+CD+DE
tu as ttes les longueurs,