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AlexosLCS
@AlexosLCS
January 2021
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Bonjour tout le monde ! J'aurais besoins d'aide pour cet exercice, si quelqu'un peu m'aider, merci d'avance ☺ PS : c'est l'exercice 1
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grr12
Pi + 3 < pi + 4 donc
1/pi + 3 > 1/pi + 4
b) v3 - 1 > V2 - 1 donc
1/V3 - 1 < V2 - 1
1 votes
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1/pi + 3 > 1/pi + 4
b) v3 - 1 > V2 - 1 donc
1/V3 - 1 < V2 - 1