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Mcharreau
@Mcharreau
May 2019
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Bonjour tout le monde pouvez-vous m'aider s'il vous plaît.
Développer puis réduire
C= x(x+1)(x+2)
Factoriser
D=(4x-5)(x+1)+(x+1)²
E=9x²-6x+1
F= (3x+2)²- (x-5)²
merci beaucoup
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maudmarine
Verified answer
Bonjour,
Développer puis réduire
C= x(x+1)(x+2)
C = x (x² + 2x + x + 2)
C = x
³ + 2x² + x² + 2
C = x
³ + 3x² + 2
Factoriser
D=(4x-5)(x+1)+(x+1)²
D = (x + 1) (x + 1 + 4x - 5)
D = (x + 1) (5x - 4)
E=9x²-6x+1
E = (3x - 1) (3x - 1)
E = (3x - 1)²
F= (3x+2)²- (x-5)²
F = (3x + 2 - x + 5) (3x + 2 + x - 5)
F = (2x + 7) (4x - 3)
2 votes
Thanks 1
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Verified answer
Bonjour,Développer puis réduire
C= x(x+1)(x+2)
C = x (x² + 2x + x + 2)
C = x³ + 2x² + x² + 2
C = x³ + 3x² + 2
Factoriser
D=(4x-5)(x+1)+(x+1)²
D = (x + 1) (x + 1 + 4x - 5)
D = (x + 1) (5x - 4)
E=9x²-6x+1
E = (3x - 1) (3x - 1)
E = (3x - 1)²
F= (3x+2)²- (x-5)²
F = (3x + 2 - x + 5) (3x + 2 + x - 5)
F = (2x + 7) (4x - 3)