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Adrien09022000
@Adrien09022000
May 2019
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Bonjour tout le monde pouvez vous m'aidez svp:
On considère l'expression E= (3x+2)²-(5-2x)²
1) Développer et réduire E
2) Factoriser E en utiliant une identité remarquable
3)Résoudre l'équation : (x+7) (5x-3)=0
merci beaucoup :)
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winner123
Verified answer
Bonjour
E = 9 x² + 12 x + 4 - ( 25 - 20 x + 4 x²)
E = 9 x² + 12 x + 4 - 25 + 20 x - 4 x²
E =
5 x² + .32 x - 21
E = ( 3 x + 2 + 5 - 2 x) ( 3 x + 2 - 5 + 2 x)
E =
( x + 7) ( 5 x - 3)
E = 0
soit x + 7 = 0 ⇒
x = - 7
soit 5 x - 3 = 0 ⇒ 5 x = 3 et
x = 3/5
1 votes
Thanks 1
adrien09022000
merci
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Verified answer
BonjourE = 9 x² + 12 x + 4 - ( 25 - 20 x + 4 x²)
E = 9 x² + 12 x + 4 - 25 + 20 x - 4 x²
E = 5 x² + .32 x - 21
E = ( 3 x + 2 + 5 - 2 x) ( 3 x + 2 - 5 + 2 x)
E = ( x + 7) ( 5 x - 3)
E = 0
soit x + 7 = 0 ⇒ x = - 7
soit 5 x - 3 = 0 ⇒ 5 x = 3 et x = 3/5