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Roses123
@Roses123
May 2019
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Bonjour tout le monde,pourriez vous m'aidez pour ceci? Merci d'avance
On considérè l'expression : A=( x-3)(3x+2)-2(x-3).
1.Développer A.
2.Factoriser A et vérifier que A =3B ou B=x(x-3).
3.Déterminer tous les nombres x tels que (x-3)(3x+2)-2(x-3)=0.
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Commentaires (1)
1)
A=( x-3)(3x+2)-2(x-3)
= 3x²
+2x-9x-6-2x+6
= 3x²-9x
2)
A=3x²-9x=3(x²-3x)=3[x(x-3)]
B=x(x-3)
donc : A=3B
3)
(x-3)(3x+2)-2(x-3) = 0
⇒ 3[x(x-3)] = 0
⇒ x(x-3) = 0
⇒ x=0 ou x-3=0
⇒ x=0 ou x=3
1 votes
Thanks 1
Roses123
Merci beaucoup
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A=( x-3)(3x+2)-2(x-3)
= 3x² +2x-9x-6-2x+6
= 3x²-9x
2)
A=3x²-9x=3(x²-3x)=3[x(x-3)]
B=x(x-3)
donc : A=3B
3)
(x-3)(3x+2)-2(x-3) = 0
⇒ 3[x(x-3)] = 0
⇒ x(x-3) = 0
⇒ x=0 ou x-3=0
⇒ x=0 ou x=3