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nenettespeed
@nenettespeed
January 2021
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Bonjour URGENT pour demain c'est noté, je stress et je ne comprends rien !
Merci de m'éviter la bulle !!!! classe seconde
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trudelmichel
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Bonjour,
M milieu deAB
AB diamétre M centre du cercle
AB=1+x
R=(1+x)/2
MC=(1+x)/2
IM=AB-(AI+MB)
IM=1+x-(1+(x+1)/2)
IM=1+x-1-(x+1)/2
IM=x-(x+1)/2
IM=(2x-x+1)/2
IM= (x-1)/2
triangle rectangle ICM
IC²=CM²-IM²
IC²=((1+x)/2)²-((x-1)/2)²
IC²=(1+x²+2x)/4 -(x²-2x+1)/4
IC²=(1+x²+2x-x²+2x-1)/4
IC²=4x/4
IC²=x
IC=racine(x)
pour tracer
IC=racine(3)
IC²=3
3=((1+x)/2)²-((x-1)/2)²
3=1+x²+2x-1-x²+2x
3=4x/4
3=x
on trace AI=1
puis IB= 3
M milieu de AB
cercle de rayon 2
Perpendiculaire IC à AB
IC coupe le cercle en C
IC=racine(3)
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Verified answer
Bonjour,M milieu deAB
AB diamétre M centre du cercle
AB=1+x
R=(1+x)/2
MC=(1+x)/2
IM=AB-(AI+MB)
IM=1+x-(1+(x+1)/2)
IM=1+x-1-(x+1)/2
IM=x-(x+1)/2
IM=(2x-x+1)/2
IM= (x-1)/2
triangle rectangle ICM
IC²=CM²-IM²
IC²=((1+x)/2)²-((x-1)/2)²
IC²=(1+x²+2x)/4 -(x²-2x+1)/4
IC²=(1+x²+2x-x²+2x-1)/4
IC²=4x/4
IC²=x
IC=racine(x)
pour tracer
IC=racine(3)
IC²=3
3=((1+x)/2)²-((x-1)/2)²
3=1+x²+2x-1-x²+2x
3=4x/4
3=x
on trace AI=1
puis IB= 3
M milieu de AB
cercle de rayon 2
Perpendiculaire IC à AB
IC coupe le cercle en C
IC=racine(3)