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Titi56fun
@Titi56fun
April 2019
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Bonjour voici ma question: Résoudre l'équations suivante:
d) |0,3x²+2x - 5| = -1
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meheriohere
D) On transforme pour mettre en une équation
0.3x²+2x-5+1=0
0.3x²+2x-4 =0 est de la forme ax² +bx+c=0 avec a=0.3, b=2 et c=-4
Puis on calcul le discriminant DELTA :
D = b²-4ac
D = 2²-4*0.3*(-4)
D = 4+4.8
D = 8.8
D > 0 le trinome admet deux racines distinctes
X1 = -b-racine de D / 2a
X1 = -2-racine de 8.8 /0.6
X1 = -8.2774656580638
X2 = -b+racine de D /2a
X2 = -2+racine de 8.8 /0.6
X2 = 1.6107989913971
Donc 0.3x²+2x-4=0 quand x=-8.2774656580638 et x=1.6107989913971
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0.3x²+2x-5+1=0
0.3x²+2x-4 =0 est de la forme ax² +bx+c=0 avec a=0.3, b=2 et c=-4
Puis on calcul le discriminant DELTA :
D = b²-4ac
D = 2²-4*0.3*(-4)
D = 4+4.8
D = 8.8
D > 0 le trinome admet deux racines distinctes
X1 = -b-racine de D / 2a
X1 = -2-racine de 8.8 /0.6
X1 = -8.2774656580638
X2 = -b+racine de D /2a
X2 = -2+racine de 8.8 /0.6
X2 = 1.6107989913971
Donc 0.3x²+2x-4=0 quand x=-8.2774656580638 et x=1.6107989913971