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Matissou59
@Matissou59
May 2019
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Bonjour voici mon exercice :
Développer et réduire :
F= 2(3x+5)
G= x au carré (7x-8)
H= (2x+3)(5x+4)
Merci d'avance pour vos réponses.
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Commentaires (1)
F = 2(3x+5) = 2*3x + 2*5 = 6x + 10
G = x²(7x-8) = x²*7x - x²*8 = 7x³-8x²
H = (2x+3)(5x+4) = 2x*5x + 2x*4 + 3*5x + 3*4
= 10x² + 8x + 15x + 12
= 10x² + 23x + 12
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yoyososo017oy2k54
Salut !
F= 2 (3x+5)
= 6x+10
G= x^2 (7x-8)
=7x^3 - 8x^2
H= (2x+3) (5x+4)
= 2x ( 5x+4 ) + 3(5x+4)
= 10x^2 + 8x + 15x +12
= 10x^2 + 23x + 12
Voilà. ..
0 votes
Thanks 0
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G = x²(7x-8) = x²*7x - x²*8 = 7x³-8x²
H = (2x+3)(5x+4) = 2x*5x + 2x*4 + 3*5x + 3*4
= 10x² + 8x + 15x + 12
= 10x² + 23x + 12
F= 2 (3x+5)
= 6x+10
G= x^2 (7x-8)
=7x^3 - 8x^2
H= (2x+3) (5x+4)
= 2x ( 5x+4 ) + 3(5x+4)
= 10x^2 + 8x + 15x +12
= 10x^2 + 23x + 12
Voilà. ..