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FrostMath
@FrostMath
May 2019
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Bonjour voici quelques équations a produits nul :
(4y - 5)-(y+4) = 0
3a(2a-6) = 0
(3a-5)(2a-4) - (3a-5)(1-4a) = 0
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nonotata
Bonjour
(4y - 5)-(y+4) = 0
4y-5-y-4 =0
3y -9 =0
3y =9
y =9/3
y =3
3a(2a-6) = 0
3a =0 2a-6 =0
a =0/3 2a =6
a = 0 a = 6/2 =3
(3a-5)(2a-4) - (3a-5)(1-4a) = 0
(3a-5)(2a-4-1+4a) =0
(3a-5)(6a-5) =0
3a-5= 0 6a-5 =0
3a =5 6a = 5
a = 5/3 a = 5/6
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(4y - 5)-(y+4) = 0
4y-5-y-4 =0
3y -9 =0
3y =9
y =9/3
y =3
3a(2a-6) = 0
3a =0 2a-6 =0
a =0/3 2a =6
a = 0 a = 6/2 =3
(3a-5)(2a-4) - (3a-5)(1-4a) = 0
(3a-5)(2a-4-1+4a) =0
(3a-5)(6a-5) =0
3a-5= 0 6a-5 =0
3a =5 6a = 5
a = 5/3 a = 5/6