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CapitaineAwesome
@CapitaineAwesome
April 2019
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Bonjour! Voici une expression à développer et à réduire si vous le voulez bien.
Développer et réduire l'expression (2n+5)(2n-5) où n est un nombre quelconque.
En utilisant le calcul effectué ci-dessus, calculer 205 x 195
Merci d'avance!
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nathalienouts
(2n+5)(2n-5)
= 4n²-10n+10n-25
= 4n²-25
(2x100+5)(2x100-5) = 4x100²-25 = 40 000-25 = 39 975
2 votes
Thanks 1
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= 4n²-10n+10n-25
= 4n²-25
(2x100+5)(2x100-5) = 4x100²-25 = 40 000-25 = 39 975