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Bonjour,

[tex]4(x-5)+3x\\=4x-20+3x\\=7x-20[/tex]

[tex]3x(5-x)-4x\\=15x-3x^2-4x\\=-3x^2+11x[/tex]

[tex]7(3x-2)+6(1-x)\\=21x-14+6-6x\\=15x-8[/tex]

Réponse :

a. 4(x-5)+3x = 4x -20 +3x = 7x - 20

b. 3x(5-x)-4x = 15x -3x² -4x = - 3x² + 11x

c. 7(3x-2) +6(1-x)​ = 21x - 14 + 6 - 6x = 15x - 8