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Soulaimane20
@Soulaimane20
May 2019
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Bonjour,
aidez moi svp à faire cet exercice.
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anylor
Bonjour
1)
testons
2n² -8n +6 =0
delta = b²-4ac
= (-8)² -4×2×6
=16=4²
x1 =(-b -√Δ)/2a
=1
x2=(-b +√Δ)/2a
=3
donc VRAI car
pour n = 1 et n=3 un =0
2) faux
car un < 0 seulement si n=2
car
théorème du signe du trinôme
Un < 0 si 1<n<3
3)
faux
car un> 0
si n <1 ou n >3
un n'est pas supérieur à 0 pour tout n
un =0 si n =1
un <0 si n =2
un = 0 si n = 3
1 votes
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Bonjour tout le monde, svp j'ai besoin de votre aide pour faire cet exercice. Urgent !!!!
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1)
testons
2n² -8n +6 =0
delta = b²-4ac
= (-8)² -4×2×6
=16=4²
x1 =(-b -√Δ)/2a
=1
x2=(-b +√Δ)/2a
=3
donc VRAI car
pour n = 1 et n=3 un =0
2) faux
car un < 0 seulement si n=2
car
théorème du signe du trinôme
Un < 0 si 1<n<3
3)
faux
car un> 0
si n <1 ou n >3
un n'est pas supérieur à 0 pour tout n
un =0 si n =1
un <0 si n =2
un = 0 si n = 3