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ichenille
@ichenille
June 2021
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bonjour,aidez moi svp, je ne comprend rien aux identités remarquables merci a vous
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nonotata
B = x²-9+(x-3)(3x+7)
developper
b = x²+9 +3x²+7x-9x-21
b = 4x² -2x -12
factoriser
b = x²-9+(x-3)(3x+7)
x²+9 est de la forme (x-3)(x+3) donc
b = (x-3)(x+3)+(x+3)(3x+7)
b = (x+3)(x-3 +3x+7)
b =(x+3) (4x +4)
b = 4(x+3)(x+1)
donc pour x = 3
b = 4(x+3)(x+1)
b = 4(3+3)(3+1)
b = 4(6)*(4)
b = 4(24)
b = 144
tu fais la meme chose pour les 2 autres
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svp aidez moi c pour demain merci
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je reposte ce devoir car c'est pour demain merci d'avance
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celui nla est pour demain aussi aidez moi svp merci
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aidez svp pour ces calculs, je suis nulle merci
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voici encore des calculs, merci d'avances
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developper
b = x²+9 +3x²+7x-9x-21
b = 4x² -2x -12
factoriser
b = x²-9+(x-3)(3x+7)
x²+9 est de la forme (x-3)(x+3) donc
b = (x-3)(x+3)+(x+3)(3x+7)
b = (x+3)(x-3 +3x+7)
b =(x+3) (4x +4)
b = 4(x+3)(x+1)
donc pour x = 3
b = 4(x+3)(x+1)
b = 4(3+3)(3+1)
b = 4(6)*(4)
b = 4(24)
b = 144
tu fais la meme chose pour les 2 autres