Articles
Register
Sign In
Search
ichenille
@ichenille
June 2021
1
114
Report
bonjour,aidez moi svp, je ne comprend rien aux identités remarquables merci a vous
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
nonotata
B = x²-9+(x-3)(3x+7)
developper
b = x²+9 +3x²+7x-9x-21
b = 4x² -2x -12
factoriser
b = x²-9+(x-3)(3x+7)
x²+9 est de la forme (x-3)(x+3) donc
b = (x-3)(x+3)+(x+3)(3x+7)
b = (x+3)(x-3 +3x+7)
b =(x+3) (4x +4)
b = 4(x+3)(x+1)
donc pour x = 3
b = 4(x+3)(x+1)
b = 4(3+3)(3+1)
b = 4(6)*(4)
b = 4(24)
b = 144
tu fais la meme chose pour les 2 autres
0 votes
Thanks 1
More Questions From This User
See All
ichenille
June 2021 | 0 Respostas
Responda
ichenille
June 2021 | 0 Respostas
Responda
ichenille
June 2021 | 0 Respostas
svp aidez moi c pour demain merci
Responda
ichenille
June 2021 | 0 Respostas
je reposte ce devoir car c'est pour demain merci d'avance
Responda
ichenille
June 2021 | 0 Respostas
celui nla est pour demain aussi aidez moi svp merci
Responda
ichenille
June 2021 | 0 Respostas
Responda
ichenille
June 2021 | 0 Respostas
Derniers calculs, encore besoin de votre aide merci
Responda
ichenille
June 2021 | 0 Respostas
aidez svp pour ces calculs, je suis nulle merci
Responda
ichenille
June 2021 | 0 Respostas
voici encore des calculs, merci d'avances
Responda
ichenille
June 2021 | 0 Respostas
Responda
×
Report "bonjour,aidez moi svp, je ne comprend rien aux identités remarquables merci a vous.... Pergunta de ideia de ichenille"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
developper
b = x²+9 +3x²+7x-9x-21
b = 4x² -2x -12
factoriser
b = x²-9+(x-3)(3x+7)
x²+9 est de la forme (x-3)(x+3) donc
b = (x-3)(x+3)+(x+3)(3x+7)
b = (x+3)(x-3 +3x+7)
b =(x+3) (4x +4)
b = 4(x+3)(x+1)
donc pour x = 3
b = 4(x+3)(x+1)
b = 4(3+3)(3+1)
b = 4(6)*(4)
b = 4(24)
b = 144
tu fais la meme chose pour les 2 autres