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Rambo
@Rambo
April 2019
2
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Bonjour,J'ai besoin d' une aide extremement rapide car j' ai DM pour demain sur la factorisation et j' ai beau m' entrainer deçus je n' y arrive pas l' expression est:
(4x-5)(x-3)-(3x+1)(4x-5) (ce sont des x est non pas des fois)
merci d' avance
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telephone16
Factorisation
(4x -5)
(x -3) -(3x+1)
(4x-5)
(4x -5)(x-3 -3x -1)
(4x-5) (-2x -4)
1 votes
Thanks 1
audreydu53
A= (4x-5)(x-3)-(3x+1)(4x-5)
A= (4x-5)[x-3-(3x+1)]
A= (4x-5)(x-3-3x-1)
A= (4x-5)(-2x-4)
0 votes
Thanks 1
audreydu53
Ahah!:P Derien c'est normal! ;)
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(4x -5)(x -3) -(3x+1)(4x-5)
(4x -5)(x-3 -3x -1)
(4x-5) (-2x -4)
A= (4x-5)[x-3-(3x+1)]
A= (4x-5)(x-3-3x-1)
A= (4x-5)(-2x-4)