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guess123
@guess123
January 2021
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Bonjour,j'arrive pas à résoudre cette équation 3(x+1)au carré -5>op
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aymanemaysae
Bonsoir ;
3(x+1)² - 5 > 0 ⇒ (x+1)² - 5/3 > 0 ⇒ (x+1)² > 5/3
⇒ |x+1| > √(5/3) ⇒ x+1 < -√(5/3) ou x+1 > √(5/3)
⇒ x < -1 - √(5/3) ou x > -1 + √(5/3)
⇒ x ∈ ]-∞ ; -1 - √(5/3) [ ∪ ] -1 + √(5/3) ; +∞[ .
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3(x+1)² - 5 > 0 ⇒ (x+1)² - 5/3 > 0 ⇒ (x+1)² > 5/3
⇒ |x+1| > √(5/3) ⇒ x+1 < -√(5/3) ou x+1 > √(5/3)
⇒ x < -1 - √(5/3) ou x > -1 + √(5/3)
⇒ x ∈ ]-∞ ; -1 - √(5/3) [ ∪ ] -1 + √(5/3) ; +∞[ .