Articles
Register
Sign In
Search
Steliner
@Steliner
May 2019
2
104
Report
Bonjour,je suis en 4ème.
Pouvez-vous m'aider à mon exercice mathématiques ?
Si oui.
Je vous remercie d'avance.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
Christine17
Verified answer
AB=5cm
DC=9cm donc EC=4cm
4²+h²=5²
donc h²=25-16=9=3²
h=3
0 votes
Thanks 1
Commentaires
Bonjour,
on sait que DC =9cm
AB = 5cm
⇒EC =9-5 = 4cm
BEC rectangle en B :
on cherche BE
⇒pythagore
BC² = BE²+EC²
5² = BE²+4²
BE² = 5²-4²
BE = √9 = 3cm
⇒
h = 3cm
0 votes
Thanks 0
More Questions From This User
See All
steliner
February 2021 | 0 Respostas
Responda
steliner
February 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
steliner
January 2021 | 0 Respostas
Responda
×
Report "Bonjour,je suis en 4ème. Pouvez-vous m'aider à mon exercice mathématiques ? Si oui. Je vous remerci.... Pergunta de ideia de Steliner"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
AB=5cmDC=9cm donc EC=4cm
4²+h²=5²
donc h²=25-16=9=3²
h=3
on sait que DC =9cm
AB = 5cm
⇒EC =9-5 = 4cm
BEC rectangle en B :
on cherche BE
⇒pythagore
BC² = BE²+EC²
5² = BE²+4²
BE² = 5²-4²
BE = √9 = 3cm
⇒h = 3cm