Articles
Register
Sign In
Search
xorionx
@xorionx
January 2021
1
154
Report
Bonjour,
Je suis en première S et voici un exercice dm sur la trigonométrie sur lequel je bloque un peu.
Est-ce que quelqu'un pourrait m'aider s'il vous plaît?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
ProfdeMaths1
Verified answer
Cos(a)=3/√10
sin(a)=1/√10
cos(b)=2/√5
sin(b)=1/√5
cos(c)=1/√2
sin(c)=1/√2
ainsi :
sin(b).cos(c)+sin(c).cos(b)
=1/√5.1/√2+1/√2.2/√5
=3/√10
=cos(a)
donc c-b=a
or c=π/4 donc π/4-b=a
finalement :
a+b+c=π/4-b+b+π/4
donc
a+b+c=π/2
0 votes
Thanks 1
More Questions From This User
See All
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
xorionx
January 2021 | 0 Respostas
Responda
Xorionx
June 2019 | 0 Respostas
Responda
Xorionx
June 2019 | 0 Respostas
Responda
Xorionx
June 2019 | 0 Respostas
Responda
×
Report "Bonjour,Je suis en première S et voici un exercice dm sur la trigonométrie sur lequel je bloque un p.... Pergunta de ideia de xorionx"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Cos(a)=3/√10sin(a)=1/√10
cos(b)=2/√5
sin(b)=1/√5
cos(c)=1/√2
sin(c)=1/√2
ainsi :
sin(b).cos(c)+sin(c).cos(b)
=1/√5.1/√2+1/√2.2/√5
=3/√10
=cos(a)
donc c-b=a
or c=π/4 donc π/4-b=a
finalement :
a+b+c=π/4-b+b+π/4
donc a+b+c=π/2