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xorionx
@xorionx
January 2021
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Bonjour,
Je suis en première S et voici un exercice dm sur la trigonométrie sur lequel je bloque un peu.
Est-ce que quelqu'un pourrait m'aider s'il vous plaît?
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ProfdeMaths1
Verified answer
Cos(a)=3/√10
sin(a)=1/√10
cos(b)=2/√5
sin(b)=1/√5
cos(c)=1/√2
sin(c)=1/√2
ainsi :
sin(b).cos(c)+sin(c).cos(b)
=1/√5.1/√2+1/√2.2/√5
=3/√10
=cos(a)
donc c-b=a
or c=π/4 donc π/4-b=a
finalement :
a+b+c=π/4-b+b+π/4
donc
a+b+c=π/2
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Verified answer
Cos(a)=3/√10sin(a)=1/√10
cos(b)=2/√5
sin(b)=1/√5
cos(c)=1/√2
sin(c)=1/√2
ainsi :
sin(b).cos(c)+sin(c).cos(b)
=1/√5.1/√2+1/√2.2/√5
=3/√10
=cos(a)
donc c-b=a
or c=π/4 donc π/4-b=a
finalement :
a+b+c=π/4-b+b+π/4
donc a+b+c=π/2