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Abcd56
@Abcd56
April 2019
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-Bonjour,pouvez-vous m'aidez
résoudre les équations suivantes:
1) resoudre x³-3x-2=1x-2
2) montrer que x³-3x-2=(x+1)²(x-2)
3) Résoudre x³-3x-2=0
Merci d'avance,19 points
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Commentaires (4)
Verified answer
X³ - 3x - 2 = x - 2
x³ - 3x - x - 2 + 2 = 0
x³ - 4x = 0
x(x² - 4) = 0
x = 0 ou x² - 4 = 0
ou x² = 4
ou x = - 2 ou x = 2
S= {- 2 ; 0 ; 2}
===============================================
(x + 1)²(x - 2)
= (x - 2)(x² + 2x + 1)
= x³ + 2x² + x - 2x² - 4x - 2
= x³ - 3x - 2
==============================================
x³ - 3x - 2 = 0
(x - 2)(x + 1)² = 0
x - 2 = 0 ou x + 1 = 0
x = 2 ou x = - 1
S= {- 1 ; 2}
1 votes
Thanks 1
Abcd56
merciiii beaucoup mille merci<3
maika1
slt tu peux m aider pour mon devoir de svt stp
marokinaa2121
@CYGNUS Bonjour est ce que tu pourrais m'aider à mon exercice ? Merci de ta réponse :)
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Verified answer
X³ - 3x - 2 = x - 2x³ - 3x - x - 2 + 2 = 0
x³ - 4x = 0
x(x² - 4) = 0
x = 0 ou x² - 4 = 0
ou x² = 4
ou x = - 2 ou x = 2
S= {- 2 ; 0 ; 2}
===============================================
(x + 1)²(x - 2)
= (x - 2)(x² + 2x + 1)
= x³ + 2x² + x - 2x² - 4x - 2
= x³ - 3x - 2
==============================================
x³ - 3x - 2 = 0
(x - 2)(x + 1)² = 0
x - 2 = 0 ou x + 1 = 0
x = 2 ou x = - 1
S= {- 1 ; 2}