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Maria50
@Maria50
May 2019
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Bonjours , j'ai absolument besoin d'aide pour cet exercice svp☺
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nadiab
Bonjour,
Pour le triangle BAC
cos(angle) = côté adjacent / hypoténuse .
cos(angle ABC) = 4.1 /12
cos(angle ABC) = 0.34
angle B= cos-1(0.34166666)
angle B= 70.02° ≈ 70°
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Lista de comentários
Pour le triangle BAC
cos(angle) = côté adjacent / hypoténuse .
cos(angle ABC) = 4.1 /12
cos(angle ABC) = 0.34
angle B= cos-1(0.34166666)
angle B= 70.02° ≈ 70°