Bonjours je voudrais de l'aide pour un exercices de maths s'il vous plait. On considère l'égalité : .... Pergunta de ideia deFlash05

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5y + 15 = -10 -2y
5y+2y=-10-15
7y=-25
y=-25/7

A) 5y = -2y -25
A) 5y+2y = -25
A)7y = -25
A) y = -25/7

B) 7y + 15 = -10

B) 7y = -10-15
B) 7y = -25
B) y = -25/7

C) 15 = -7y -10
C) 7y = -10-15
C) 7y = -25
C) y =-25/7

D) 5y +25= -2y
D) 5y+2y=-25
D) 7y = -25
y = -25/7

Flash05 Merci énormément

Arafat2514 Bonjour ^^

5y + 15 = -10 - 2y
5y + 2y = -15 - 10
7y = -25
x = $\frac{-25}{7}$ = -3.6

A = 5y = -2y - 25
A = 5y + 2y = -25
A = 7y = -25
x = $\frac{-25}{7}$ = -3.6

B = 7y + 15 = -10
B = 7y = -15 - 10
B = 7y = 25
B = $\frac{25}{7}$ = 3.6

C = 15 = -7y - 10
C = 7y = -15 - 10
C = 7y = 25
C = 25/7 = 3.6

D = 5y + 25 = -2y
D = 5y + 2y = - 25
D = 7y = -25
D = -25/7 = -3.6

Voilà, j'espère avoir pu vous aider ^^

Arafat2514 excuser moi

Arafat2514 mais je ne trouve pas la (les) faute (s) que j'ai fait

Arafat2514 ah oui je vois mrc ^^

Arafat2514 oui ^^ mais je ne peux plus le modifier :-?

Arafat2514 5y + 15 = -10 - 2y 5y + 2y = -15 - 10 7y = -25 y = [tex] \frac{-25}{7} [/tex] = -3.6 A = 5y = -2y - 25 A = 5y + 2y = -25 A = 7y = -25 y = [tex] \frac{-25}{7} [/tex] = -3.6 B = 7y + 15 = -10 B = 7y = -15 - 10 B = 7y = -25 y = [tex] \frac{25}{7} [/tex] = -3.6 C = 15 = -7y - 10 C = 7y = -15 - 10 C = 7y = -25 y = 25/7 = -3.6 D = 5y + 25 = -2y D = 5y + 2y = - 25 D = 7y = -25 y = -25/7 = -3.6

Arafat2514 voilà^^ dsl pour ces erreurs ^^

Arafat2514 5y + 15 = -10 - 2y 5y + 2y = -15 - 10 7y = -25 y = -25/7 = -3.6 A = 5y = -2y - 25 A = 5y + 2y = -25 A = 7y = -25 y = -25/7 = -3.6 B = 7y + 15 = -10 B = 7y = -15 - 10 B = 7y = -25 y = 25/7 = -3.6 C = 15 = -7y - 10 C = 7y = -15 - 10 C = 7y = -25 y = 25/7 = -3.6 D = 5y + 25 = -2y D = 5y + 2y = - 25 D = 7y = -25 y = -25/7 = -3.6

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