Bsr
= x²+(x+5)(x²+9x+30)-25
= (x-5)(x+5)+(x+5)(x²+9x+30)
= (x+5)(x-5+x²+9x+30)
= (x+5)(10x-5+x²+30)
= (x+5)(10x+25+x²)
= (x+5)(x²+10x+25)
= (x+5)³
Voilà !
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Bsr
= x²+(x+5)(x²+9x+30)-25
= (x-5)(x+5)+(x+5)(x²+9x+30)
= (x+5)(x-5+x²+9x+30)
= (x+5)(10x-5+x²+30)
= (x+5)(10x+25+x²)
= (x+5)(x²+10x+25)
= (x+5)³
Voilà !