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landrycoralie
@landrycoralie
January 2021
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BONJOUUUUR !
Développer les expressions : 2(x+5)+(6x-1)(4x-3) (3x+4) au carré - (x+1) Factoriser : 2x (x-3)-9 (x-3) 9x au carré-42x+49 (7x+2) au carré -64
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totolekoala
Bonsoooir :)
1)
2(x+5)+(6x-1)(4x-3) = 2x + 10 + 24x²-18x-4x+3 = 24x² -20x+13
(3x+4)² - (x+1) = 9x² + 2*(3x*4) + 16 - x - 1 = 9x² + 24x + 16 - x- 1 = 9x² +23x+15
2)
2x(x-3)-9(x-3) = (x-3)(2x-9)
9x²-42x+49 =(3x)²+3x(14)+49=3x(3x+14)+49
(7x+2)²-64 = (7x+2)²-(8)²
a²-b² c'est (a-b)(a+b) donc
(7x+2)²-64 = (7x+2-8)(7x+2+8)=(7x-6)(7x+10)
Bonne soirée !
Totolekoala
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Lista de comentários
1) 2(x+5)+(6x-1)(4x-3) = 2x + 10 + 24x²-18x-4x+3 = 24x² -20x+13
(3x+4)² - (x+1) = 9x² + 2*(3x*4) + 16 - x - 1 = 9x² + 24x + 16 - x- 1 = 9x² +23x+15
2) 2x(x-3)-9(x-3) = (x-3)(2x-9)
9x²-42x+49 =(3x)²+3x(14)+49=3x(3x+14)+49
(7x+2)²-64 = (7x+2)²-(8)²
a²-b² c'est (a-b)(a+b) donc
(7x+2)²-64 = (7x+2-8)(7x+2+8)=(7x-6)(7x+10)
Bonne soirée !
Totolekoala