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Petitnuage36
@Petitnuage36
May 2019
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Bonsoir !
Alors j'ai fait la correction de cette exercice et j'ai la réponse cependant quelqu'un pourrait-il realiser ce calcul avec des détails car je n'arrive pas à comprendre comment la professeur la réalisé
Merci d'avance !
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rosiemuller2000
Verified answer
Coucou
(x-1)³ -(x+1)(x-1)² -(x-1)(1-2x)
= (x-1)²(x-1) -(x+1)(x²-2x+1) -(x-2x²-1+2x)
= (x²-2x+1)(x-1) -(x³-2x²+x+x²-2x+1) -(x-2x²-1+2x)
= x³-x²-2x²+2x+x-1 -(x³ -x² -x +1) -(-2x²+3x-1)
= -2x² +3x -1 +x-1 +2x² -3x +1
= -1 +x -1 +1
= x + 1
donc c'est bin une fonction affine puisque c'est de la forme ax +b
voila j espere t avoir aider
2 votes
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Verified answer
Coucou(x-1)³ -(x+1)(x-1)² -(x-1)(1-2x)
= (x-1)²(x-1) -(x+1)(x²-2x+1) -(x-2x²-1+2x)
= (x²-2x+1)(x-1) -(x³-2x²+x+x²-2x+1) -(x-2x²-1+2x)
= x³-x²-2x²+2x+x-1 -(x³ -x² -x +1) -(-2x²+3x-1)
= -2x² +3x -1 +x-1 +2x² -3x +1
= -1 +x -1 +1
= x + 1
donc c'est bin une fonction affine puisque c'est de la forme ax +b
voila j espere t avoir aider