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Lola93170
@Lola93170
January 2021
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bonsoir, besoin d'aide pour l'exo 2
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scoladan
Verified answer
Bonjour,
1) f(0)
forme développée 3 : f(0) = 2*0² - 4*0 - 6 = -6
2) f(√3)
idem : f(√3) = 2*3 - 4*√3 - 6 = -4√3
3) f(x) = 0
forme factorisée 2 : 2(x - 3)(x + 1) = 0 ⇒ x = 3 ou x = -1
4) f(x) = 10
⇔ f(x) - 10 = 0
donc forme 4 : 2(x - 4)(x + 2) = 0 ⇒ x = 4 ou x = -2
5) f(1)
forme canonique 1 : f(1) = 2(1 - 1)² - 8 = -8
6) f(x) = -6
forme développée 3 : 2x² - 4x - 6 = -6 ⇔ 2x² - 4x = 0 ⇔ 2x(x - 2) = 0
⇒ x = 0 ou x = 2
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Lola93170
January 2021 | 0 Respostas
Bonjour pouvez vous me corriger mon essais en vous remerciant d'avance
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Bonsoir quelqu'un pourrait m'aider , merci d'avance
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Lola93170
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Bonjour , il faut simplifier le calcul suivant le plus possible : -5,6 x 0,25 x (-8) sur -2 x 2,8
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Lista de comentários
Verified answer
Bonjour,1) f(0)
forme développée 3 : f(0) = 2*0² - 4*0 - 6 = -6
2) f(√3)
idem : f(√3) = 2*3 - 4*√3 - 6 = -4√3
3) f(x) = 0
forme factorisée 2 : 2(x - 3)(x + 1) = 0 ⇒ x = 3 ou x = -1
4) f(x) = 10
⇔ f(x) - 10 = 0
donc forme 4 : 2(x - 4)(x + 2) = 0 ⇒ x = 4 ou x = -2
5) f(1)
forme canonique 1 : f(1) = 2(1 - 1)² - 8 = -8
6) f(x) = -6
forme développée 3 : 2x² - 4x - 6 = -6 ⇔ 2x² - 4x = 0 ⇔ 2x(x - 2) = 0
⇒ x = 0 ou x = 2