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celinemarchess
@celinemarchess
January 2021
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bonsoir, c est vraiment très urgent, je bug sur cet exercice, aidez moi svp, merci, niveau seconde
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aymanemaysae
Bonsoir ;
1) On a : 2(x-9/7)(3x+1) = 2(3x² + x -27/7 x - 9/7) = 2(3x² - 20/7 x - 9/7)
= 6x² - 40/7 x - 18/7 = f(x) ,
donc f(x) = 2(x-9/7)(3x+1) .
2)
a) f(0) = 6*0² - 40/7 * 0 - 18/7 = - 18/7 .
f(9/7) = 2(9/7 - 9/7)(3*9/7 + 1) = 2 * 0 * (27/7 + 1) = 0 .
b) f(x) = 0 donc 2(x-9/7)(3x+1)=0 donc x-9/7=0 ou 3x+1=0
donc x=9/7 ou x= -1/3 .
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1) On a : 2(x-9/7)(3x+1) = 2(3x² + x -27/7 x - 9/7) = 2(3x² - 20/7 x - 9/7)
= 6x² - 40/7 x - 18/7 = f(x) ,
donc f(x) = 2(x-9/7)(3x+1) .
2)
a) f(0) = 6*0² - 40/7 * 0 - 18/7 = - 18/7 .
f(9/7) = 2(9/7 - 9/7)(3*9/7 + 1) = 2 * 0 * (27/7 + 1) = 0 .
b) f(x) = 0 donc 2(x-9/7)(3x+1)=0 donc x-9/7=0 ou 3x+1=0
donc x=9/7 ou x= -1/3 .