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danyfichant
@danyfichant
January 2021
2
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bonsoir
developper (x+3)²-(2x+1)²
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PAU64
Bonsoir
x² + 6 x + 9 - ( 4 x² + 4 x + 1)
= x² + 6 x + 9 - 4 x² - 4 x - 1
= - 3 x² + 2 x + 8
3 votes
Thanks 1
danyfichant
merci bcp
PAU64
de rien ;)
winner123
Verified answer
(x + 3)² - (2x + 1)²
= x² + 2 * x * 3 + 3² - [(2x)² + 2 * 2x * 1 + 1²]
= x² + 6x + 9 - (4x² + 4x + 1)
= x² + 6x + 9 - 4x² - 4x - 1
= - 3x² + 2x + 8
Les * désignent "fois".
2 votes
Thanks 1
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Lista de comentários
x² + 6 x + 9 - ( 4 x² + 4 x + 1)
= x² + 6 x + 9 - 4 x² - 4 x - 1
= - 3 x² + 2 x + 8
Verified answer
(x + 3)² - (2x + 1)²= x² + 2 * x * 3 + 3² - [(2x)² + 2 * 2x * 1 + 1²]
= x² + 6x + 9 - (4x² + 4x + 1)
= x² + 6x + 9 - 4x² - 4x - 1
= - 3x² + 2x + 8
Les * désignent "fois".