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Thomas83150
@Thomas83150
May 2019
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Bonsoir et merci d'avance
1)Développer et factoriser les expression suivantes
A=(3x+1)^2-(3x+1)(4x+2)
B=(5x+4)(x+3)-(x+3)
C=(x-4)(x+4)-(x-4)(5x+1)
2) x= -3
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loulakar
Verified answer
Bonjour,
1) Développer :
A = (3x + 1)^2 - (3x + 1)(4x + 2)
A = 9x^2 + 6x + 1 - (12x^2 + 6x + 4x + 2)
A = 9x^2 - 12x^2 + 6x - 6x - 4x - 2
A = -3x^2 - 4x - 2
B = (5x + 4)(x + 3) - (x + 3)
B = 5x^2 + 15x + 4x + 12 - x - 3
B = 5x^2 + 18x + 9
C = (x - 4)(x + 4) - (x - 4)(5x + 1)
C = x^2 + 4x - 4x - 16 - (5x^2 + x - 20x - 4)
C = x^2 - 5x^2 -16 + 19x + 4
C = -4x^2 + 19x - 12
Factoriser :
A = (3x + 1)^2 - (3x + 1)(4x + 2)
A = (3x + 1)(3x + 1 - 4x - 2)
A = (3x + 1)(-x - 1)
B = (5x + 4)(x + 3) - (x + 3)
B = (x + 3)(5x + 4 - 1)
B = (x + 3)(5x + 3)
C =(x - 4)(x + 4) - (x - 4)(5x + 1)
C = (x - 4)(x + 4 - 5x - 1)
C = (x - 4)(-4x + 3)
2) x = -3
A = (3 * (-3) + 1)(-(-3) - 1)
A = (-9 + 1)(3 - 1)
A = (-8) * 2
A = (-16)
B = (-3 + 3)(5 * (-3) + 3)
B = 0 * (-15 + 3)
B = 0
C = (-3 - 4)(-4 * (-3) + 3)
C = (-7) * (12 + 3)
C = (-7) * 15
C = (-105)
1 votes
Thanks 1
loulakar
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Verified answer
Bonjour,1) Développer :
A = (3x + 1)^2 - (3x + 1)(4x + 2)
A = 9x^2 + 6x + 1 - (12x^2 + 6x + 4x + 2)
A = 9x^2 - 12x^2 + 6x - 6x - 4x - 2
A = -3x^2 - 4x - 2
B = (5x + 4)(x + 3) - (x + 3)
B = 5x^2 + 15x + 4x + 12 - x - 3
B = 5x^2 + 18x + 9
C = (x - 4)(x + 4) - (x - 4)(5x + 1)
C = x^2 + 4x - 4x - 16 - (5x^2 + x - 20x - 4)
C = x^2 - 5x^2 -16 + 19x + 4
C = -4x^2 + 19x - 12
Factoriser :
A = (3x + 1)^2 - (3x + 1)(4x + 2)
A = (3x + 1)(3x + 1 - 4x - 2)
A = (3x + 1)(-x - 1)
B = (5x + 4)(x + 3) - (x + 3)
B = (x + 3)(5x + 4 - 1)
B = (x + 3)(5x + 3)
C =(x - 4)(x + 4) - (x - 4)(5x + 1)
C = (x - 4)(x + 4 - 5x - 1)
C = (x - 4)(-4x + 3)
2) x = -3
A = (3 * (-3) + 1)(-(-3) - 1)
A = (-9 + 1)(3 - 1)
A = (-8) * 2
A = (-16)
B = (-3 + 3)(5 * (-3) + 3)
B = 0 * (-15 + 3)
B = 0
C = (-3 - 4)(-4 * (-3) + 3)
C = (-7) * (12 + 3)
C = (-7) * 15
C = (-105)