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Hasnaa95190
@Hasnaa95190
May 2019
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Bonsoir , il faut que je résout cette équation : (2x + 1)^2 = (x + 3)^2
Et s'il vous plaît n'utilisez pas la formule delta car on ne la pas encore fait
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nadiab
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Résoudre cette équation : (2x + 1)²=
(x + 3)²
(2x + 1)²= (x + 3)²
(2x + 1)²- (x + 3)²=0
[(2x+1)-(x+3)] [(2x+1+x+3)]
(2x+1-x-3)(2x+1+x+3)
(x-2)((3x+4)
x-2=0 ou 3x+4=0
x=2 x= -3/4 S= {-3/4 ; 2 }
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Verified answer
Résoudre cette équation : (2x + 1)²= (x + 3)²(2x + 1)²= (x + 3)²
(2x + 1)²- (x + 3)²=0
[(2x+1)-(x+3)] [(2x+1+x+3)]
(2x+1-x-3)(2x+1+x+3)
(x-2)((3x+4)
x-2=0 ou 3x+4=0
x=2 x= -3/4 S= {-3/4 ; 2 }