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Lili6245
@Lili6245
May 2019
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Bonsoir j'ai besoin d'aide pour calculer A=(5-3√2)(5+3√2)
Merci de votre aide
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trudelmichel
Verified answer
Bonjour,
indentité remarquable
(a+b)(a-b)=a²-b²
A=(5-3√2)(5+3√2)
a=5
b=3√2
A=(a-b)(a+b)
A=a²-b²
A=5²-(3√2)²
A=25-(9(2))
A=25-18
A=7
1 votes
Thanks 1
oussama16
Verified answer
Bonjour :
A=(5-3
√2) (5+3√2) c'est une identité remarquable qui prend la forme de (a+b)(a-b)=a²-b²
Donc :(5-3√2)(5+3√2)=5²-(3√2)²=25-18=7
Voilà, une bonne journée.
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Lista de comentários
Verified answer
Bonjour,indentité remarquable
(a+b)(a-b)=a²-b²
A=(5-3√2)(5+3√2)
a=5
b=3√2
A=(a-b)(a+b)
A=a²-b²
A=5²-(3√2)²
A=25-(9(2))
A=25-18
A=7
Verified answer
Bonjour :A=(5-3√2) (5+3√2) c'est une identité remarquable qui prend la forme de (a+b)(a-b)=a²-b²
Donc :(5-3√2)(5+3√2)=5²-(3√2)²=25-18=7
Voilà, une bonne journée.