Articles
Register
Sign In
Search
xluuciee
@xluuciee
June 2021
0
75
Report
Bonsoir, j'ai un probleme sur une question :
Soit l'équation (E) : 2 e^ex = e^x + 1
a) En posant X = e^x , montrer que l'équation (E) revient à résoudre l'équation ( X - 1 ) ( 2 X + 1 ) = 0
b) En déduire la résolution de l'équation (E)
Merci pour votre aide!!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
More Questions From This User
See All
xluuciee
June 2021 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Pourquoi la culture hors sol respecte mieux l'environnement ??
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Calculer : (0.02q+2) - (0.02q+2.01)Merci d'avance :)
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
Xluuciee
April 2019 | 0 Respostas
Responda
×
Report "Bonsoir, j'ai un probleme sur une question : Soit l'équation (E) : 2 e^ex = e^x + 1 a) En posant X.... Pergunta de ideia de xluuciee"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.