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xluuciee
@xluuciee
June 2021
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Bonsoir, j'ai un probleme sur une question :
Soit l'équation (E) : 2 e^ex = e^x + 1
a) En posant X = e^x , montrer que l'équation (E) revient à résoudre l'équation ( X - 1 ) ( 2 X + 1 ) = 0
b) En déduire la résolution de l'équation (E)
Merci pour votre aide!!
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