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Cloclo76
@Cloclo76
April 2019
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Bonsoir, j'ai vraiment besoin d'aide pour ce dm qui est pour demain.. c'est urgent je comprend pas ...
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Koukine11e
(Cos x + sin x)^2 + (cos x - sin x)^2 = 2
alors:
Cos^2x + sin^2x + 2cosxsinx + cos^2x + sin^2x - 2cosxsinx =
(On sait que sin^2+cos^2=1)
alors = cos^2x+sin^2x + cos^2x + sin^2x = 1+1=2
1 + (tan x)^2 = 1/(cos x)^2
Alors:
(Tan x)^2 = (sinx/cosx)^2
1+ sinx^2/cosx^2 = cosx^2/cosx^2 + sinx^2/cosx^2
(On sait que sin^2+cos^2=1)
donc = 1/cosx^2
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Thanks 1
Cloclo76
merci énormément pour ta réponse ! :)
Cloclo76
J'ai essayer de recopier mais je comprend pas... tout :/ ça : ^2 veut bien dire 2 au carrée ? Et malgré tes explications j'ai toujours pas compris
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Bonjour, pouvez-vous m'aidez svp URGENT
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alors:
Cos^2x + sin^2x + 2cosxsinx + cos^2x + sin^2x - 2cosxsinx =
(On sait que sin^2+cos^2=1)
alors = cos^2x+sin^2x + cos^2x + sin^2x = 1+1=2
1 + (tan x)^2 = 1/(cos x)^2
Alors:
(Tan x)^2 = (sinx/cosx)^2
1+ sinx^2/cosx^2 = cosx^2/cosx^2 + sinx^2/cosx^2
(On sait que sin^2+cos^2=1)
donc = 1/cosx^2