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Valentinedu6299
@Valentinedu6299
April 2019
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Bonsoir jaimerais que quelqu'un m'aide a résoudre 2(y)² +
y -3 = 0
Merci
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isapaul
Verified answer
Bonsoir
2y² + √3 * y -3 = 0
Δ = 3 + 24 = 27 alors √Δ = √27
deux solutions
y ' = (-√3 - √27)/4 = (-√3 - √(9*3)) / 4 = (-√3 - 3√3)/4 = -√3
y" = (-√3 + √27)/4 = (-√3 + √(9*3) / 4 = (2√3)/4 = √3 / 2
Bonne soirée
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valentinedu6299
Merci beaucoup
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y -3 = 0
Lista de comentários
Verified answer
Bonsoir2y² + √3 * y -3 = 0
Δ = 3 + 24 = 27 alors √Δ = √27
deux solutions
y ' = (-√3 - √27)/4 = (-√3 - √(9*3)) / 4 = (-√3 - 3√3)/4 = -√3
y" = (-√3 + √27)/4 = (-√3 + √(9*3) / 4 = (2√3)/4 = √3 / 2
Bonne soirée