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Serined
@Serined
January 2021
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Bonsoir,
J'aurais besoin d'aide pour ces deux factorisations d'expression.
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loulakar
Verified answer
Salut,
c(x) = (x+3)(2x-1) + (x+4)(x+3)
= (x+3) [(2x-1) + (x+4)]
= (x+3) (2x-1+x+4)
= (x+3) (3x+3)
= 3 (x+3) (x+1)
d(x) = (1-2x)² - (1-2x)
= (1-2x) [(1-2x) - 1 ]
= (1-2x) (1-2x-1)
= -2x (1-2x)
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Verified answer
Salut,c(x) = (x+3)(2x-1) + (x+4)(x+3)
= (x+3) [(2x-1) + (x+4)]
= (x+3) (2x-1+x+4)
= (x+3) (3x+3)
= 3 (x+3) (x+1)
d(x) = (1-2x)² - (1-2x)
= (1-2x) [(1-2x) - 1 ]
= (1-2x) (1-2x-1)
= -2x (1-2x)