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matriip
@matriip
June 2021
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Bonsoir je n'arrive pas cet exercice . aidez mooii svp :)
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isapaul
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Bonsoir
1)
x>0.3 car sinon 10(0.3)-3 = 0 revient à Aire AEFG = 0
2)
Aire ABCD = (10x+1)²
Aire AEFG = (10x-3)²
3)
Aire Bleue = Aire ABCD -Aire AEFG
Aire Bleus = (10x+1)²-(10x-3)² identité remarquable a²-b² =(a+b)(a-b)
Aire Bleue = (10x+1+10x-3)(10x+1-10x+3) = (20x-2)(4) = 80x-8
4)
Aire Bleue = 272 cm² revient à
80x-8 = 272
80x = 280
x = 280/80 = 3.5 cm
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Verified answer
Bonsoir1)
x>0.3 car sinon 10(0.3)-3 = 0 revient à Aire AEFG = 0
2)
Aire ABCD = (10x+1)²
Aire AEFG = (10x-3)²
3)
Aire Bleue = Aire ABCD -Aire AEFG
Aire Bleus = (10x+1)²-(10x-3)² identité remarquable a²-b² =(a+b)(a-b)
Aire Bleue = (10x+1+10x-3)(10x+1-10x+3) = (20x-2)(4) = 80x-8
4)
Aire Bleue = 272 cm² revient à
80x-8 = 272
80x = 280
x = 280/80 = 3.5 cm