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louismarie77
@louismarie77
January 2021
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Bonsoir, je souhaiterais avoir une aide. Merci bcp
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winner123
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Bonsoir
A(x) = 1 - 4 x² - ( 1 - 2 x)( 2 + x)
A(x) = 1 - 4 x² - ( 2 + x - 4 x - 2 x²)
A(x) = 1 - 4 x² - 2 - x + 4 x + 2 x²
A(x) = - 2 x² + 3 x - 1
A(x) = ( 1 - 2 x ) ( 1 + 2 x) - ( 1 - 2x) ( 2 + x)
A(x) = ( 1 - 2 x) ( 1 + 2 x - 2 - x )
A(x) = ( 1 - 2 x ) ( x - 1)
A(x) = 0
soit 1 - 2 x = 0
soit x - 1 = 0
solutions = 1/2 ou 1
A(x) = - 1
A(x) = ( 1 - 2 x ) ( 2 x - 1) = - 1
A(x) = ( 1 - 2 x )( 2 x - 1) + 1 = 0
la solution est la même que précédemment
A(x) = 3 x - 1
A(x) = ( 1 - 2 x) ( x - 1) = 3 x - 1 )
A(x) = ( 1 - 2 x ) ( x - 1) - ( 3 x - 1) = 0
soit les 2 premiers facteurs sont nuls, donc même solution
soit 3 x - 1 = 0 et
x = 1/3
1 votes
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Aider moi juste pour cette question ! merci =)
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Aider moi svp a faire tout les exos de la feuille merci pour tout
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Bonjour pouvez vous m'aidez a faire cette exo ! merci
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Verified answer
BonsoirA(x) = 1 - 4 x² - ( 1 - 2 x)( 2 + x)
A(x) = 1 - 4 x² - ( 2 + x - 4 x - 2 x²)
A(x) = 1 - 4 x² - 2 - x + 4 x + 2 x²
A(x) = - 2 x² + 3 x - 1
A(x) = ( 1 - 2 x ) ( 1 + 2 x) - ( 1 - 2x) ( 2 + x)
A(x) = ( 1 - 2 x) ( 1 + 2 x - 2 - x )
A(x) = ( 1 - 2 x ) ( x - 1)
A(x) = 0
soit 1 - 2 x = 0
soit x - 1 = 0
solutions = 1/2 ou 1
A(x) = - 1
A(x) = ( 1 - 2 x ) ( 2 x - 1) = - 1
A(x) = ( 1 - 2 x )( 2 x - 1) + 1 = 0
la solution est la même que précédemment
A(x) = 3 x - 1
A(x) = ( 1 - 2 x) ( x - 1) = 3 x - 1 )
A(x) = ( 1 - 2 x ) ( x - 1) - ( 3 x - 1) = 0
soit les 2 premiers facteurs sont nuls, donc même solution
soit 3 x - 1 = 0 et x = 1/3