Articles
Register
Sign In
Search
Mwaa6633
@Mwaa6633
June 2021
1
70
Report
Bonsoir ! Je suis bloquée sur cet exercice (n 64) Si quelqu'un pouvait m'aider ! Merci beaucoup
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
nathalienouts
1) Triangle rectangle d'après le théorème de Pythagore
EF² = EG² + FG²
EG² = EF²-FG²
EG² = (13√7)²-(√175)²
EG² = 169x7-175
EG² = 1183-175
EG² = 1008
EG = √1008
EG = 12√7
2)
A = basexhauteur /2
A = EGxFG/2
A = 12√7x√175/2 or √175 = 5√7
A = 6√7x5√7
A = 30√7²
A = 30x7
A = 210
3)
p = EG+FG+EF
p = 12√7+5√7+13√7
p = 30√7
0 votes
Thanks 1
Mwaa6633
Merci beaucoup !
nathalienouts
de rien
More Questions From This User
See All
Mwaa6633
June 2021 | 0 Respostas
Responda
Mwaa6633
June 2021 | 0 Respostas
Responda
Mwaa6633
June 2021 | 0 Respostas
Responda
Mwaa6633
January 2021 | 0 Respostas
Responda
Mwaa6633
January 2021 | 0 Respostas
Bonsoir ! Je dois trouver 4 questions en espagnol en utilisant la structure " c'est ... qui ... " avec les formations el que/ las que / quien et quienes Merci beaucoup !
Responda
Mwaa6633
May 2019 | 0 Respostas
Bonsoir ! Pouvez vous m'aider pour l'exercice 56 ? Merci beaucoup !
Responda
Mwaa6633
May 2019 | 0 Respostas
Responda
Mwaa6633
May 2019 | 0 Respostas
Pouvez vous m'aider sur ces 2 exercices ? Merci beaucoup !!
Responda
Mwaa6633
May 2019 | 0 Respostas
Responda
×
Report "Bonsoir ! Je suis bloquée sur cet exercice (n 64) Si quelqu'un pouvait m'aider ! Merci beaucoup.... Pergunta de ideia de Mwaa6633"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
EF² = EG² + FG²
EG² = EF²-FG²
EG² = (13√7)²-(√175)²
EG² = 169x7-175
EG² = 1183-175
EG² = 1008
EG = √1008
EG = 12√7
2)
A = basexhauteur /2
A = EGxFG/2
A = 12√7x√175/2 or √175 = 5√7
A = 6√7x5√7
A = 30√7²
A = 30x7
A = 210
3)
p = EG+FG+EF
p = 12√7+5√7+13√7
p = 30√7