d apres le théorème de thales, AD/AB = AE/AC= DE/BC
ainsi BD = AB-AD = (AD×BC)/DE - AD = 4×12/3-4 = 12
et AE=AC×DE/BC
AE= (AE+EC)×DE/BC
AE = (AE+9)×3/12
AE = ( 27 + 3AE ) /12
12AE = 27 + 3AE
9AE = 27
AE = 3
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d apres le théorème de thales, AD/AB = AE/AC= DE/BC
ainsi BD = AB-AD = (AD×BC)/DE - AD = 4×12/3-4 = 12
et AE=AC×DE/BC
AE= (AE+EC)×DE/BC
AE = (AE+9)×3/12
AE = ( 27 + 3AE ) /12
12AE = 27 + 3AE
9AE = 27
AE = 3