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Petitnuage36
@Petitnuage36
January 2021
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Bonsoir,
Pourriez vous m'aider à mettre ces deux calculs sous la forme canonique ?
J'aimerais pouvoir comparer mes réponses et trouver mes erreurs.
Merci d'avance !
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Bonsoir,
F(x) = -2x² + 5x - 4
F(x) = -2 ( x² - 5x/2 + 2 )
F(x) = -2 [ ( x-5/4 )² - ( 5/4)² + 2 ]
F(x) = -2 ( x-5/4 )² + 25/8 -4 = -2 ( x-5/4 )² - 7/8
G(x) = 3x² - x - 1
G(x) = 3 ( x² - x/3 ) - 1
G(x) = 3 [ ( x-1/6 )² - 1/6² ] - 1
G(x) = 3 ( x -1/6 )² - 1/12 - 1 = 3 ( x-1/6 )² - 13/12
2 votes
Thanks 1
Petitnuage36
Merci de la réponse ! Ce que j'ai trouvé coïncide
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Bonsoir,F(x) = -2x² + 5x - 4
F(x) = -2 ( x² - 5x/2 + 2 )
F(x) = -2 [ ( x-5/4 )² - ( 5/4)² + 2 ]
F(x) = -2 ( x-5/4 )² + 25/8 -4 = -2 ( x-5/4 )² - 7/8
G(x) = 3x² - x - 1
G(x) = 3 ( x² - x/3 ) - 1
G(x) = 3 [ ( x-1/6 )² - 1/6² ] - 1
G(x) = 3 ( x -1/6 )² - 1/12 - 1 = 3 ( x-1/6 )² - 13/12