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Marialesens0606
@Marialesens0606
May 2019
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Bonsoir pourriez vous m'aider pour l'exercice 39
dsl pour la qualité de la photo
merci d'avance
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nguyenso9
Verified answer
Bonsoir,
1a) 1 minute = 60 s
1 h = 3 600 s
2 x 60 = 120 Mo
2 x 3 600 = 7 200 Mo
1b)
2 Mo → 1 s
100 Mo → ? s
100 / 2 = 50 s
2a)
5 Mo → 1 s
? Mo → 60 s
? Mo → 3 600 s
Je te laisse calculer :) si tu as un doute, regarde la question 1a
2b)
5 Mo → 1 s
100 Mo → ? s
A toi de calculer ! si tu as un doute, regarde la question 1b
2 votes
Thanks 1
marialesens0606
merci beaucoup c'est grave simpa
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Lista de comentários
Verified answer
Bonsoir,1a) 1 minute = 60 s
1 h = 3 600 s
2 x 60 = 120 Mo
2 x 3 600 = 7 200 Mo
1b)
2 Mo → 1 s
100 Mo → ? s
100 / 2 = 50 s
2a)
5 Mo → 1 s
? Mo → 60 s
? Mo → 3 600 s
Je te laisse calculer :) si tu as un doute, regarde la question 1a
2b)
5 Mo → 1 s
100 Mo → ? s
A toi de calculer ! si tu as un doute, regarde la question 1b