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Leanl
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May 2019
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Bonsoir pourriez vous m'expliquez ? Svp
Comment on fait pour facoriser :
(3x-4) (9x+4) - (2x-4)
Merci
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davidmartil
(3x-4)(9x+4)-(2x-4) = 27
+12x-36x-16-2x+4
= 27
-26x-12
Δ = 676 -4*27*(-12)
= 676 + 1296
= 1972
√Δ = 2
x1= 26-2
/ 54 = 13-
/ 27
x2= 13+
/ 27
la factorisation : 27(x-13-
/ 27) ( x-13+
/ 27)
1 votes
Thanks 0
Commentaires
Bonsoir ,
(3x-4) (9x+4) - (2x-4)
= 27x² + 12x - 36x - 16 - 2x + 4
= 27x² - 26x - 12 .
Δ = b² - 4ac
Δ = (-26)² - 4 × 27 × (-12)
Δ = 676 - (-1296)
Δ = 1972
x₁ = -b+√Δ/2a
x₁ = -(-26) + √1972 / 2× 27
x₁ = 26 + √1972 / 54
x₂ = -b-√Δ / 2a
x₂ = -(-26) - √1972 / 2 × 27
x₂ = 26 - √1972 / 54
S = { (26-√1972)/54 ; (26+√1972)/54 } .
1 votes
Thanks 1
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Lista de comentários
= 27 -26x-12
Δ = 676 -4*27*(-12)
= 676 + 1296
= 1972
√Δ = 2
x1= 26-2 / 54 = 13- / 27
x2= 13+ / 27
la factorisation : 27(x-13- / 27) ( x-13+ / 27)
(3x-4) (9x+4) - (2x-4)
= 27x² + 12x - 36x - 16 - 2x + 4
= 27x² - 26x - 12 .
Δ = b² - 4ac
Δ = (-26)² - 4 × 27 × (-12)
Δ = 676 - (-1296)
Δ = 1972
x₁ = -b+√Δ/2a
x₁ = -(-26) + √1972 / 2× 27
x₁ = 26 + √1972 / 54
x₂ = -b-√Δ / 2a
x₂ = -(-26) - √1972 / 2 × 27
x₂ = 26 - √1972 / 54
S = { (26-√1972)/54 ; (26+√1972)/54 } .